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4n^2+12n-112=0
a = 4; b = 12; c = -112;
Δ = b2-4ac
Δ = 122-4·4·(-112)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-44}{2*4}=\frac{-56}{8} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+44}{2*4}=\frac{32}{8} =4 $
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